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siva ramanSubject: entity conversion
Author: siva raman
Date: 21 Mar 2005 01:59 AM
Hello All,

pls help me in entity conversion in xml to xml mapping.
I need the same entity name (e.g. –) should come in output xml file.
Now I am using a entity file (with unicode values) with my xslt and get symbols instead of entities.


thanks
Siva
Postnext
Ivan PedruzziSubject: entity conversion
Author: Ivan Pedruzzi
Date: 21 Mar 2005 04:36 PM

Could you post the XSLT + XML you are using?
Postnext
siva ramanSubject: entity conversion
Author: siva raman
Date: 22 Mar 2005 09:41 AM
Hai Ivan,

thanks for your reply.

Pls find the files, by which i am transforming xml to xml.



thanks
Siva


Unknowncheck.ent
entity

Unknownconvert.xsl
xsl

Unknowninput(2).xml
input
Postnext
Ivan PedruzziSubject: entity conversion
Author: Ivan Pedruzzi
Date: 22 Mar 2005 10:14 AM
Siva

to output a dtd declaration you have to use

<xsl:output method="xml" encoding="UTF-8" doctype-system="http://public.metapress.com/dtd/TAFXML/TFJA.dtd" indent="yes"/>
Postnext
siva ramanSubject: entity conversion
Author: siva raman
Date: 22 Mar 2005 10:27 AM
Ivan

thanks for ur reply,

can u pls send reply for regarding the entity conversion.
My requirement is entity name should be same as in input xml.


thanks
Siva
Posttop
Tony LavinioSubject: entity conversion
Author: Tony Lavinio
Date: 22 Mar 2005 11:56 AM
In any XSLT engine, you cannot see the original entities.
The XML parser converts them into Unicode code-points, so XSLT only
sees them that way.

If you want to emit them again as entities, you must do the work
yourself.

XSLT 2.0 has a mechanism for handling that; you can build character-maps
(see http://www.w3.org/TR/xslt20/#character-maps for details). But there
is no way in XSLT itself to say "I saw a &tm; come in, and I want to
write it out as a &tm;" because that's the job of the serializer, which
comes AFTER the XSLT is done with the transform.

If you know the specific code-points, you can manually replace them,
but again that's harder in XSLT 1.0 since there is no search-and-replace
function like there is in 2.0, but one can be simulated. For help on
that, I would probably recommend the XSLT Cookbook by Sal Mangano.

   
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