[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Wikipedia on XML
On Fri, Aug 21, 2009 at 06:09:58PM -0700, Kurt Cagle wrote: > Keep in mind audience here. I'd be inclined rather to indicate that an XML > document is a valid SGML document as well, Strictly speaking, any valid (i.e. DTD-valid) XML document is also valid SGML document. > that for this reason there is an > implicit assumption that a DTD exists for any created XML document type, but > that current usage is increasingly to keep such DTD's implicit in favor of > more explicit definitions by other schemas. The relationship between SGML and XML is really only meaningful for XML documents with actual DTDs. It's not usefully the case that there's an implicit document type declaration, and although the vague and all-encompassing SGML definition of a document type definition might be said to apply to any document, such a remark would merely be vacuous sophistry. There's no assumption that there is a DTD for any XML document. As for (per ERH) the DTD modifying the infoset, strictly speaking the XML infoset specification gives us a way to describe the result of parsing an XML document, and since DTD processing happens as part of that process, there's no modification... although maybe I'm being overly pedantic, as it's certainly true you can end up with different results if you parse the same XML docuent but with or without its DTD. Just as you can if you use or don't use a W3C XML Schema (XSD) thta supplies default content, for example. Best, Liam -- Liam Quin, W3C XML Activity Lead, http://www.w3.org/People/Quin/ http://www.holoweb.net/~liam/ * http://www.fromoldbooks.org/
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