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Re: is there a way to break out of the xsl:for-each loop ?

• To: "'xml-dev@l...'" <xml-dev@l...>
• Subject: Re: is there a way to break out of the xsl:for-each loop ?
• From: Liam Quin <liam@w...>
• Date: Tue, 23 Mar 2004 11:20:38 -0500
• In-reply-to: <5.2.0.9.0.20040323072707.00bd6f28@p...>
• References: <830BF4914C3C4B4EB1C438D93ABF897A044423@l...> <5.2.0.9.0.20040323072707.00bd6f28@p...>
• User-agent: Mutt/1.5.5.1+cvs20040105i

On Tue, Mar 23, 2004 at 07:31:49AM -0800, G. Ken Holman wrote:
> At 2004-03-23 08:38 -0600, Bill Riegel wrote:
> >What to look thru a listOfNodes, and set contents on a variable, foundIt,
> >when I found what I am looking for, then break.
> 
> XSLT does not work this way ... the semantics for an <xsl:for-each> are 
> different than a programmer's "for loop".

To amplify on that a little...

"for-each" can be read as saying, make a sequence in which each element
is the result of a single evaluation of this contained expression for
every matching item.

In functional programming terms it's a mapping from one sequence to
another.

An XSLT engine does not need to evaluate the for-each in any particular
order -- all that matters is that the results are generated in the
appropriate order.  This is similar to a C compiler optimising by
changing expression evaluation order, and is not usually noticeable
unless you start using things with side effects
(e.g. ++j * ++i + --i * --j might or might not do what you expect in C)

I hope this helps.  But it really is a different way of thinking about
things.

Liam

-- 
Liam Quin, W3C XML Activity Lead, http://www.w3.org/People/Quin/
http://www.holoweb.net/~liam/

• References:
  • is there a way to break out of the xsl:for-each loop ?
    • From: Bill Riegel <BRiegel@l...>
  • Re: is there a way to break out of the xsl:for-each loop ?
    • From: "G. Ken Holman" <gkholman@C...>

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