[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: is there a way to break out of the xsl:for-each loop ?

• To: "'xml-dev@l...'" <xml-dev@l...>
• Subject: Re: is there a way to break out of the xsl:for-each loop ?
• From: "G. Ken Holman" <gkholman@C...>
• Date: Tue, 23 Mar 2004 07:31:49 -0800
• In-reply-to: <830BF4914C3C4B4EB1C438D93ABF897A044423@l...>

At 2004-03-23 08:38 -0600, Bill Riegel wrote:
>What to look thru a listOfNodes, and set contents on a variable, foundIt,
>when I found what I am looking for, then break.

XSLT does not work this way ... the semantics for an <xsl:for-each> are 
different than a programmer's "for loop".

><xsl:variable name="foundIt">
>         <xsl:for-each select="$listofNodes">
>                 <xsl:if test="string(current()) = $mySearchItem">
>                         <!-- break out of look if found what I am looking
>for -->
>                         <xsl:break>
>                 </xsl:if>
>         </xsl:for-each>
></xsl:variable>
>
><!-- do something with foundIt -->

XSLT does not work this way either ... variables are bound with a value and 
cannot change within their scope.

You haven't described what you want to do to your information, you have 
only described a non-functional programmer's approach to a coding pattern.

Perhaps you need something like:

   <xsl:for-each select="$listofNodes[.=$mySearchItem]">
     <!--do something with found nodes equal to my search item-->
   </xsl:for-each>

When using XSLT you merely address the nodes that you want to process 
rather than attempting a circuitous design pattern based on traditional 
programming techniques.

I hope this helps.

............................ Ken

--
World-wide on-site corporate, govt. & user group XML/XSL training.
G. Ken Holman                 mailto:gkholman@C...
Crane Softwrights Ltd.          http://www.CraneSoftwrights.com/x/
Box 266, Kars, Ontario CANADA K0A-2E0    +1(613)489-0999 (F:-0995)
Male Breast Cancer Awareness  http://www.CraneSoftwrights.com/x/bc

• Follow-Ups:
  • Re: is there a way to break out of the xsl:for-each loop ?
    • From: Liam Quin <liam@w...>

• References:
  • is there a way to break out of the xsl:for-each loop ?
    • From: Bill Riegel <BRiegel@l...>

• Prev by Date: Re: is there a way to break out of the xsl:for-each loop ?
• Next by Date: RE: is there a way to break out of the xsl:for-each loop ?
• Previous by thread: Re: is there a way to break out of the xsl:for-each loop ?
• Next by thread: Re: is there a way to break out of the xsl:for-each loop ?
• Index(es):
  • Date
  • Thread