[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] how the parser locate dtd files
hi, I am new to xml and need to do a quick prototype of how to retrieve information from other web site using xml format. I got a parsing error of ** Parsing error, line 2, uri null Relative URI "my.dtd"; cannot be resolved without a document URI. I am using Sun's xml parser, and the code looks like URL source = new URL(url); URLConnection conn = source.openConnection(); conn.setDoInput(true); InputStream is = conn.getInputStream(); input = Resolver.createInputSource("text/xml;charset=UTF-8", is, false, "http"); parser = ParserFactory.makeParser(); parser.setDocumentHandler(this); parser.setErrorHandler(this); parser.parse(input); The document that I am retrieving from the url looks like <?xml version="1.0" encoding="iso-8859-1"?> <!DOCTYPE mydoc SYSTEM "my.dtd"> ..... The my.dtd is at the same location as the document, but obviously the parser doesn't know how to resolve it. What I need to do for configuring the parser? I am kind of lost by reading the document, any help will be greatly appreciated. Thanks. Weihong. xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev@i... Archived as: http://www.lists.ic.ac.uk/hypermail/xml-dev/ and on CD-ROM/ISBN 981-02-3594-1 To unsubscribe, mailto:majordomo@i... the following message; unsubscribe xml-dev To subscribe to the digests, mailto:majordomo@i... the following message; subscribe xml-dev-digest List coordinator, Henry Rzepa (mailto:rzepa@i...)
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