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RE: how the parser locate dtd files

• From: "Weihong Xie" <wxie@g...>
• To: "David Brownell" <david-b@p...>
• Date: Thu, 28 Oct 1999 12:49:26 -0700

Thanks for your reply, I've try to create the InputSource directly by

	input = new InputSource(url)

but the sun's xml tr2 parser doesn't like it, it gives me

	java.io.IOException: Push back buffer is full
		at java.io.PushbackInputStream.unread(PushbackInputStream.java:211)
		at com.sun.xml.parser.XmlReader.useEncodingDecl(Compiled Code)
		at com.sun.xml.parser.XmlReader.<init>(XmlReader.java:240)
		at com.sun.xml.parser.XmlReader.createReader(XmlReader.java:86)
		...

I think it's because it's not using http protocal although the url is an
http url string. One thing that I may not make it clear is the xml
page/content is dynamically generated at the web server.

Thanks for any help.

Weihong.

> -----Original Message-----
> From: David Brownell [mailto:david-b@p...]
> Sent: Thursday, October 28, 1999 12:24 PM
> To: Weihong Xie
> Subject: Re: how the parser locate dtd files
>
>
> Weihong Xie wrote:
> >
> > hi,
> >
> > I am new to xml and need to do a quick prototype of how to retrieve
> > information from other web site using xml format. I got a
> parsing error of
> >
> > ** Parsing error, line 2, uri null
> >    Relative URI "my.dtd"; cannot be resolved without a document URI.
>
> Clearly you're not providing the document URI ...
>
>
> > I am using Sun's xml parser, and the code looks like
>
> ... why don't you just do "input = new InputSource (url)"?
>
> That provides the base URI to the parser, and is a _lot_ simpler.
>
> - Dave
>
>
>
> >
> >             URL source = new URL(url);
> >             URLConnection conn = source.openConnection();
> >             conn.setDoInput(true);
> >             InputStream is = conn.getInputStream();
> >
> >             input =
> Resolver.createInputSource("text/xml;charset=UTF-8", is,
> > false, "http");
> >             parser = ParserFactory.makeParser();
> >               parser.setDocumentHandler(this);
> >               parser.setErrorHandler(this);
> >               parser.parse(input);
> >
> > The document that I am retrieving from the url looks like
> >
> >         <?xml version="1.0" encoding="iso-8859-1"?>
> >         <!DOCTYPE mydoc SYSTEM "my.dtd">
> >         .....
> >
> > The my.dtd is at the same location as the document, but
> obviously the parser
> > doesn't know how to resolve it. What I need to do for configuring the
> > parser? I am kind of lost by reading the document, any help
> will be greatly
> > appreciated.
> >
> > Thanks.
> >
> > Weihong.
> >
> > xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev@i...
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>


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