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chandrasekhar ValmikiSubject: Delete the xsi:nil attribute from XML Payload
Author: chandrasekhar Valmiki
Date: 14 Feb 2013 04:14 PM
Please find the below code and let me know what I need to specify in XSLT Mapping for removing xsi:nil attribute completely.

Appreciate your quick help.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output omit-xml-declaration="yes"/>
<xsl:variable name="vDoc" select="document('')"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<xsl:copy>
<xsl:copy-of select="$vDoc/*/namespace::*

[name() = 'xsd'

or

name() = 'xsi'

]"/>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(node())]">
<xsl:copy>
<xsl:attribute name="xsi:nil">true</xsl:attribute>

<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

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Ivan PedruzziSubject: Delete the xsi:nil attribute from XML Payload
Author: Ivan Pedruzzi
Date: 14 Feb 2013 09:58 PM
What you are trying to accomplish with this?

If what you need is just dropping xsi:nil, do the following

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:template match="@xsi:nil"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>


Ivan Pedruzzi
Stylus Studio Team

   
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