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Delete the xsi:nil attribute from XML Payload
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Subject:
Delete the xsi:nil attribute from XML Payload
Author:
chandrasekhar Valmiki
Date:
14 Feb 2013 04:14 PM
Please find the below code and let me know what I need to specify in XSLT Mapping for removing xsi:nil attribute completely.
Appreciate your quick help.
<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform"
xmlns:xsd="
http://www.w3.org/2001/XMLSchema"
xmlns:xsi="
http://www.w3.org/2001/XMLSchema-instance">
<xsl:output omit-xml-declaration="yes"/>
<xsl:variable name="vDoc" select="document('')"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/*">
<xsl:copy>
<xsl:copy-of select="$vDoc/*/namespace::*
[name() = 'xsd'
or
name() = 'xsi'
]"/>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(node())]">
<xsl:copy>
<xsl:attribute name="xsi:nil">true</xsl:attribute>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
top
Subject:
Delete the xsi:nil attribute from XML Payload
Author:
Ivan Pedruzzi
Date:
14 Feb 2013 09:58 PM
What you are trying to accomplish with this?
If what you need is just dropping xsi:nil, do the following
<xsl:stylesheet version="1.0"
xmlns:xsl="
http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="
http://www.w3.org/2001/XMLSchema-instance">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:template match="@xsi:nil"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Ivan Pedruzzi
Stylus Studio Team
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