Re: Keys with duplicates should be simple

  <xsl:import href="identity.xsl"/>
  <xsl:key name="person" match="a" use="@href"/>

  <xsl:template match="person">
    <duplicate>
      <xsl:apply-templates select="a[key('person',@href)[
2]]"/>
    </duplicate>
  </xsl:template>

If it's simple I should be able to describe it simply. Here goes.

Copy all a elements that have more than one entry in the key table
indexed by their value in the href attribute.

or maybe better.......

Create a key table using the href from each a element and copy all the
entries that occur more than once in it.



On Fri, Jan 31, 2014 at 7:34 PM, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> On Fri, Jan 31, 2014 at 11:28 AM, Ihe Onwuka <ihe.onwuka@xxxxxxxxx> wrote:
>> http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201211/msg00170.html
>>
>> OP is using XSLT 2. OP only wants to find what things have duplicates.
>> Thats not a grouping problem, it's a problem that a certain variant of
>> for-each-group happens to solve but it's not the simplest way of
>> solving it.
>
>  "Things that have duplicates" is exactly what we shouldn't be seeing
> here -- to ambiguous (things, duplicates).
>
> And "simple" is also very subjective. Do you mean "short", or what?
> Does "simple" also mean efficient? Or should efficiency be of lower
> priority?
>
> As for "Things that have duplicates" -- see this -- just XPath 2 --
> not even XSLT:
>
>
>      http://stackoverflow.com/a/287360/36305
>
>
>
> --
> Cheers,
> Dimitre Novatchev
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