[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Keys with duplicates should be simple
On Fri, Jan 31, 2014 at 7:28 PM, Ihe Onwuka <ihe.onwuka@xxxxxxxxx> wrote: > On Fri, Jan 31, 2014 at 5:36 PM, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: >> On Fri, Jan 31, 2014 at 9:16 AM, Wendell Piez <wapiez@xxxxxxxxxxxxxxx> wrote: >>> For this, one could also say >>> >>> a[@href = (../a except .)/@href] >> >> >> >> Hi Wendell, >> >> I agree with every statement in your message. >> >> At the same time, I believe, that the OP wouldn't have posted the >> question in case he was allowed to use XSLT 2 -- as it is obvious that >> in XSLT 2 one should use the <xsl:for-each-group> instruction. >> >> In the unlikely case that someone is using XSLT 2 and still trying to >> use keys for grouping, this most probably means that such person isn't >> aware of the existence of the <xsl:for-each-group> instruction. >> > > http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201211/msg00170.html > Oh Wendell and just for bonus that the same thread that articulates what I hate about except. > OP is using XSLT 2. OP only wants to find what things have duplicates. > Thats not a grouping problem, it's a problem that a certain variant of > for-each-group happens to solve but it's not the simplest way of > solving it.
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|