[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Keys with duplicates should be simple
On Fri, Jan 31, 2014 at 5:36 PM, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote: > On Fri, Jan 31, 2014 at 9:16 AM, Wendell Piez <wapiez@xxxxxxxxxxxxxxx> wrote: >> For this, one could also say >> >> a[@href = (../a except .)/@href] > > > > Hi Wendell, > > I agree with every statement in your message. > > At the same time, I believe, that the OP wouldn't have posted the > question in case he was allowed to use XSLT 2 -- as it is obvious that > in XSLT 2 one should use the <xsl:for-each-group> instruction. > > In the unlikely case that someone is using XSLT 2 and still trying to > use keys for grouping, this most probably means that such person isn't > aware of the existence of the <xsl:for-each-group> instruction. > http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/201211/msg00170.html OP is using XSLT 2. OP only wants to find what things have duplicates. Thats not a grouping problem, it's a problem that a certain variant of for-each-group happens to solve but it's not the simplest way of solving it.
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