[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] XSLT stylesheet looping through the same node (recursion?)
Hi All, I would like to get all the content/text in <p> node from the XML document where <p> has a child node <strong>Interest:<strong>. Below is the listing of both XML document and XSLT stylesheet: <?xml version="1.0" encoding="UTF-8" ?> <!DOCTYPE html (View Source for full doctype...)> - <html xmlns="http://www.w3.org/1999/xhtml" xmlns:html="http://www.w3.org/1999/xhtml"> - <head> - <body ........ - ><div id="container"> + <div id="header"> <div id="postmark" /> - <div id="content"> + <div id="as1"> ....... <h1>Employee Detail</h1> - <p> <strong>Interest:</strong> <br /> Tennis <br /> Movie <br /> Swimming <br /> ..... <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns="http://www.w3.org/1999/xhtml" exclude-result-prefixes="ns"> <xsl:template match="/"> <area> - <xsl:for-each select="/ns:html/ns:body/ns:div[@id='content']/ns:p/ns:strong"> - <xsl:if test="contains(.,'Interest:')"> - <xsl:choose> - <xsl:when test="contains(.,'Interest:')"> - <interest> <xsl:value-of select="../text()" /> </interest> </xsl:when> - <xsl:otherwise> <interest>Unknown</interest> </xsl:otherwise> </xsl:choose> </xsl:if> </xsl:template> </xsl:stylesheet> The transformation process produces the following output: <?xml version="1.0" encoding="UTF-8"?> <html xmlns="http://www.w3.org/1999/xhtml"> <title>Employee Detail</title> <body> <h1>Employee Detail</h1> <interest>Tennis</interest> </body> </title> </html> One possible solution is by using recursion to go through the list of values on nodes but I am cannot think of how this could be done. Perhaps my difficulty is that I donât know how to navigate down the list of interest of the same node using xsl command. Most of the Googled articles consisted of searching for the same type of element a cross multiple nodes, where as I am looking all the values (same type anyway) in a single node. Below is the JDOM XPath solution to get the same list of values: XPath interestxpath = XPath.newInstance("/ns:html/ns:body/ns:div[@id='content']/ns:p[10]/node()"); interestxpath.addNamespace("ns", "http://www.w3.org/1999/xhtml"); java.util.List interest_list = interestxpath.selectNodes(employeejdomDocument); Iterator interest_iterator = interest_list.iterator(); while (interest_iterator..hasNext()) { interest_value = ((org.jdom.Content)interest_iterator.next()).getValue(); â¦â¦ I am new to XSLT stylesheet transformation and can do with some guidances. Many thanks again, Jack Stay connected to the people that matter most with a smarter inbox. http://au.rd.yahoo.com/galaxy/mail/tagline2/*http://au.docs.yahoo.com/mail/smarterinbox.
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