[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to 'invert' an Xpath statement please
On Tue, Aug 26, 2008 at 2:33 PM, Rens Duijsens <rens.duijsens@g...> wrote: > The normal xpath statement '//NODE' will give me: > NODE, ELEMENT (with Element 2), ELEMENT (With Element 3) > As previous replies have stated, your expression returns a single node that is an element with the name 'NODE'. If you however use this '//NODE' in an expression where a string is expected, it will be converted to a string value that is the concatanation of all text nodes that are children of descendant elements, 'Element 2Element 3', in this case. The expression: //NODE = 'Element 2Element 3' therefore also returns true. This non-intuitive behaviour (to me at least) is the reason why reading the specification or a good book to get a grasp of some basic priniciples is definitely worthwhile. If you're not ready to buy a book yet and find the W3C specification a bit terse, you could try the free online O'Reilly Commons book by John E. Simpson: http://commons.oreilly.com/wiki/index.php/XPath_and_XPointer -- Phil Fearon http://www.sketchpath.com
[Date Prev] | [Thread Prev] | [Thread Next] | [Date Next] -- [Date Index] | [Thread Index] |
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|