[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: One problem about XSD
You might try <xsd:all> <xsd:element name="a">...</xsd:element> <xsd:element name="b">...</xsd:element> <xsd:element name="c">...</xsd:element> <xsd:element name="d">...</xsd:element> <xsd:any namespace="##any" processContents="skip" /> </xsd:all> If that doesn't work (I presume it doesn't) you could try unfolding it to give every permutation. Or just do something like the following <xsd:choice maxOccurs="unbounded"> <xsd:element name="a">...</xsd:element> <xsd:element name="b">...</xsd:element> <xsd:element name="c">...</xsd:element> <xsd:element name="d">...</xsd:element> <xsd:any namespace="##any" processContents="skip" /> </xsd:choice> then use a Schematron schema to enforce the single rule <sch:rule context="whatever"> <sch:assert test="count(a)=1">There should be one a</sch:assert> <sch:assert test="count(b)=1">There should be one b</sch:assert> <sch:assert test="count(c)=1">There should be one c</sch:assert> <sch:assert test="count(d)=1">There should be one d</sch:assert> </sch:rule> Cheers Rick Jelliffe Juny Yin wrote: > > Hi, xml-dev experts: > > Now I have one problem about XSD as the following: > I want to define the contents model of an element, For example the > element is <EleParent> and currently it > has four children elements:<a>,<b>,<c>,<d>. these children elements > can appear in any order under <EleParent>. > For extensibility any other children elements can be added to > <EleParent> in any order. > > How can I write the schema for this requirement? > Who can give me the answer? > > Thanks a lot. > > Best regards. > > > > > Juny.Yin >
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