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RE: Please help me to understand a basic concept.

• To: "Alessandro Barabesi" <alex@b...>
• Subject: RE: Please help me to understand a basic concept.
• From: "Manos Batsis" <m.batsis@b...>
• Date: Fri, 5 Jul 2002 12:22:16 +0300
• Cc: <xml-dev@l...>
• Thread-index: AcIkAqi/zd3pE6yNRyOW+IOzYiWwtAAAeJAg
• Thread-topic: Please help me to understand a basic concept.

Alessandro,

You'll have more chances to get a response when using plain-text email
;-)

Remember in HTML, you link to a stylesheet (CSS) using a 

<link rel="stylesheet" href="stylesheet/path.css" type="text/css"/>

Quite similarly, in XML documents you do the same using a Processing
Instruction instead of a link element:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="test.xslt"?>
<documentElement>
  <!-- rest of document -->
</documentElement>

You specify whether the stylesheet is text/css or text/xsl in the type
attribute.

Hth,

Manos



-----Original Message-----
From: Alessandro Barabesi [mailto:alex@b...] 
Sent: Friday, July 05, 2002 11:58 AM
To: xml-dev@l...
Subject:  Please help me to understand a basic concept.


Hi everybody

I hope someone will be so ncie to spend few minutes to help me.
I started to look at XML 2 days ago so please be patient, I know my
problem is probably a stupid one. 

What I don't seem to understand is:
if XML allowes me to structure content so that, with stylesheets, that
content
can be visualized, in a browser, in hundreds of different ways, how can
I 
associate a stylesheet to a XML document which is available at a certain
URL?
At the moment the only solutions I found is using vbscript with
Microsoft.XMLDOM object:

set xmlDoc = server.createObject("Microsoft.XMLDOM")
xmlDoc.async="false"
set xsl = Server.CreateObject("Microsoft.XMLDOM")
xsl.async = false
xsl.load(Server.MapPath("my_local_stylesheet.xsl"))
xmlDoc.load("http://some.web.server/some_file.xml")
Response.Write(xmlDoc.transformNode(xsl))

I have the feeling that I am missing a basic concept here and probably
what I am trying
to do can be done very easily but I dont seem to be able to find out
how.

Thanks,

Alex

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