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RE: Java: interface methods with same name and signatur e

• From: "Fuchs, Matthew" <matthew.fuchs@c...>
• To: 'Ronald Bourret' <rpbourret@r...>, xml-dev <xml-dev@l...>
• Date: Fri, 26 Oct 2001 18:16:26 -0700

Ron,

You haven't been programming C++ recently, have you?

A Java interface merely specifies a set of method signatures that any implementing class must have actual implementations of.  If it implements more than one interface, then it must provide actual implementations for the _union_ of those sets - i.e., if class fooimp implements interface foo1, that just means that it must have _a_ method with signature "public void foo()".  Likewise, if class fooimp implements interface foo2, that just means that it must have _a_ method with a signature "public void foo()".  And if it implements both, then it still only needs to have _a_ method with that signature - not 2.

So the syntax is simply:

public class fooimp implements foo1, foo2 {
  public void foo(){
  ...
  }
}

Matthew

> -----Original Message-----
> From: Ronald Bourret [mailto:rpbourret@r...]
> Sent: Friday, October 26, 2001 2:34 PM
> To: xml-dev
> Subject: Java: interface methods with same name and
> signature
>
>
> Sorry about the non-XML topic...
>
> Suppose I have two interfaces, both of which have a method
> with the same
> name and the same signature. For example:
>
>    public interface foo1 {public void foo()}
>    public interface foo2 {public void foo()}
>
> Now suppose I want a single object to implement both interfaces:
>
>    public class fooimp implements foo1, foo2
>
> Calling methods shouldn't be a problem, as I can cast:
>
>    fooimp fi = new fooimp();
>    (foo1)fi.foo();
>    (foo2)fi.foo();
>
> But what is the syntax for actually implementing the methods? This is
> clearly a problem:
>
>    public class fooimp implements foo1, foo2
>    {
>       public void foo() {...} // from foo1
>       public void foo() {...} // from foo2
>    }
>
> I couldn't find anything in the Java spec...
>
> Thanks,
>
> -- Ron
>
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