[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Define a root in a DTD
christine.coisy@m... wrote: > I have few elements in a DTD and I want to explicity declare one as the root > to be used in XML, not the others, is there a way for that ? As has been pointed out by others, you can't do this in the DTD. What hasn't been mentioned is that you effectively create this constraint in the document type declaration: <!DOCTYPE myRoot SYSTEM "uri-of-some-dtd"> ...says that this document is of type "myRoot", and thus its root/document element is going to be one of those "myRoot" elements, a type of element for which the content model can be found in the specified DTD. - Mike _____________________________________________________________________________ mike j. brown, software engineer | xml/xslt: http://skew.org/xml/ in denver, colorado, USA | personal: http://hyperreal.org/~mike/ ------------------------------------------------------------------ The xml-dev list is sponsored by XML.org, an initiative of OASIS <http://www.oasis-open.org> The list archives are at http://lists.xml.org/archives/xml-dev/ To unsubscribe from this elist send a message with the single word "unsubscribe" in the body to: xml-dev-request@l...
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