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Re: XSL and Namespace Question

• From: "Steve Muench" <smuench@u...>
• To: "Michael Wiechers" <MichaelW@r...>
• Date: Sun, 9 Apr 2000 17:57:34 -0700

Future XSL questions are best directed to xsl-list@m...

Here's some helpful hints...

| <NavigationElement xlink:href="index.xml" xlink:title="Overview"
| xml-href="true"/>
|
| I don't get the href value using <xsl:value-of select="@href"/>.

For the first one, you need to qualify href with xlink:href...

<?xml version="1.0"?>
<NavigationElement xmlns:xlink="urn:xlink"
     xlink:href="index.xml"
     xlink:title="Overview"
     xml-href="true"/>

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xlink="urn:xlink" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
  <xsl:template match="/NavigationElement">
    Href = <xsl:value-of select="@xlink:href"/>
  </xsl:template>
</xsl:stylesheet>

| <Meta xmlns="meta.dtd">
| <Title>
| title
| </Title>
| </Meta>
|
| <xsl:value-of select="Meta/Title"/>, works only if i remove the xmlns
| declaration.

For the second one, you're hitting a limitation of
XPath 1.0 regarding default namespaces. You must
explicitly associate a prefix with the namespace uri
"meta.dtd" and then use that prefix to find Meta/Title
as meta:Meta/meta:Title as in:

<Meta xmlns="meta.dtd">
 <Title>title</Title>
</Meta>

<?xml version="1.0"?>
<xsl:stylesheet xmlns:M="meta.dtd" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
  <xsl:template match="/">
    Title = <xsl:value-of select="M:Meta/M:Title"/>
  </xsl:template>
</xsl:stylesheet>

______________________________________________________________
Steve Muench, Lead XML Evangelist & Consulting Product Manager
Business Components for Java & XSQL Servlet Development Teams
Oracle Rep to the W3C XSL Working Group



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    • From: Marty McKeever at Work <marty.mckeever@g...>

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  • XSL and Namespace Question
    • From: Michael Wiechers <MichaelW@r...>

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