[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: If SAX == lex, then what == yacc?

• From: "James Tauber" <jtauber@j...>
• To: "Ron Daniel" <RDaniel@D...>, "Anthony B. Coates" <abcoates@T...>
• Date: Tue, 23 Nov 1999 20:54:12 -0500

> [Ron Daniel]  A tool that took a DTD and generated a SAX
> DocumentHandler for parsing instances that are to conform
> to the DTD. (This much is not too hard to do for basic element
> and attribute declarations.)
>
> The next step would be to add the equivalent
> of yacc actions (e.g.  $$ = $1 + $2  if my memory of yacc
> serves) to the DTD so that in addition to validating the
> instance you can store it into a desired structure, perform
> arbitrary calculations, etc.

Right. This is pretty much what I've started doing with FOP. I have a
schema-like document with additional calculations in it.

James


xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev@i...
Archived as: http://www.lists.ic.ac.uk/hypermail/xml-dev/ and on CD-ROM/ISBN 981-02-3594-1
To unsubscribe, mailto:majordomo@i... the following message;
unsubscribe xml-dev
To subscribe to the digests, mailto:majordomo@i... the following message;
subscribe xml-dev-digest
List coordinator, Henry Rzepa (mailto:rzepa@i...)

• References:
  • RE: If SAX == lex, then what == yacc?
    • From: Ron Daniel <RDaniel@D...>

• Prev by Date: RE: msxsl error
• Next by Date: re: RE: Why I Hate Palmtops (was: Re: SGML, XML and SML)
• Previous by thread: RE: If SAX == lex, then what == yacc?
• Next by thread: Re: If SAX == lex, then what == yacc?
• Index(es):
  • Date
  • Thread