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[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Extending Types in xml schema
I think the OP was trying to extend a type comprising a repeating choice by adding another branch to that choice. The base type was (a|b|c)* and he wanted the derived type to be (a|b|c|d)*. I'm only interpreting for him because I'm curious about the answer to that question. Jeff ----- Original Message ----- From: "Henry S. Thompson" <ht@c...> To: "Craig Edmunds" <craig.edmunds@c...> Cc: <xml-dev@l...> Sent: Friday, October 31, 2003 9:04 AM Subject: Re: Extending Types in xml schema > Not entirely clear what your required functionality is. > > You could get flexible functionality, without multiple types being > involved, as follows: > > Schema 1: > <xs:element name="slug" abstract="true"/> > <xs:element name="br" substitutionGroup="slug"/> > <xs:element name="p" type="textBaseType" substitutionGroup="slug"/> > <xs:element name="span" type="spanType" substitutionGroup="slug"/> > <xs:element name="ul" type="ulType" substitutionGroup="slug"/> > <xs:element name="table" type="tableType" substitutionGroup="slug"/> > <xs:complexType name="textBaseType" mixed="true"> > <xs:element ref="slug" minOccurs="0" maxOccurs="unbounded"/> > </xs:complexType> > > > Schema 2: > > <xs:include schemaLocation="schema 1"/> > <xs:element name="li" type="tableType" substitutionGroup="slug"/>
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