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Scott RennerSubject: selecting nodes in another XML document
Author: Scott Renner
Date: 05 Aug 2005 12:39 PM
I'm trying to select an element and its children from another document, based upon the value of an element in my first document. I know I don't have the correct syntax to select the correct items.

Here is a example.

First document
...
<doc>
<device>
<model>1234AB></model>
</device>
</doc>

Second document

<devices>
<model id="1234AB">
<feature>1234</feature>
<color>Red</color>
</model>
</devices>

Output should be:
<doc>
<device>
<model>1234AB></model>
<feature>1234</feature>
<color>Red</color>
</device>
</doc>

Here is what I have come up with:
<xsl:template match="/doc/device">
<xsl:copy-of select="document('ConfigBase.xml',/devices/model[@id='model'])"/>
</xsl:template>
This doesn't work because @id='model' is looking for the literal "model" as the id. How do I reference the current value of "model" in the @id statement?

Thanks!

Scott
Postnext
Ivan PedruzziSubject: selecting nodes in another XML document
Author: Ivan Pedruzzi
Date: 05 Aug 2005 01:51 PM
Scott,

You have to use a variable like in the following code

<xsl:template match="/doc/device">
<xsl:variable name="model" select="model"/>
<xsl:copy-of select="document('ConfigBase.xml',/devices/model[@id=$model])"/>
</xsl:template>

Hope this helps
Ivan Pedruzzi
Stylus Studio Team
Postnext
Scott RennerSubject: selecting nodes in another XML document
Author: Scott Renner
Date: 05 Aug 2005 03:01 PM
That did the trick!

Thanks
Postnext
Scott RennerSubject: selecting nodes in another XML document
Author: Scott Renner
Date: 05 Aug 2005 04:18 PM
Well, I think I'm almost there, but I still have a problem.

If the first file is:
<doc>
<version>1.0</version>
<date>12/12/04</date>
<model>1234AB</model>
</doc>

and the second file is
<devices>
<model id="1234AB>
<feature>1234</feature>
<color>Red</color>
</model>
</devices>

the xsl file is:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="ISO-8859-1"/>
<xsl:template match="/config/device">
<xsl:variable name="model" select="model"/>
<xsl:copy-of select="document('ConfigBase.xml')/config/device/model[@id=$model]/*"/>
</xsl:template>
</xsl:stylesheet>

The output is now
<?xml version="1.0" encoding="UTF-16"?>
1.012/12/04
<feature>1234</feature>
<color>Red</color>

The lines that do not match the template, the values are just being output. How do I get the stylesheet to output the original XML line with the element tags still in place?

Scott
Posttop
Ivan PedruzziSubject: selecting nodes in another XML document
Author: Ivan Pedruzzi
Date: 05 Aug 2005 04:48 PM
Assuming that the main input is main.xml
<doc>
<version>1.0</version>
<date>12/12/04</date>
<model>1234AB</model>
</doc>

and the second document is ConfigBase.xml
<config>
<device>
<model id="1234AB>
<feature>1234</feature>
<color>Red</color>
</model>
</device>
</config>

you should be able to do the following

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="ISO-8859-1"/>

<xsl:template match="/">
<root>
<!-- use for-each in case your main.xml contains more then one model -->
<xsl:for-each select="/doc/model">
<xsl:variable name="model" select="."/>
<xsl:copy-of select="document('ConfigBase.xml')/config/device/model[@id=$model]/*"/>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>

Hoep this helps
Ivan Pedruzzi
Stylus Studio Team

   
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