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Jeffrey LynchSubject: XSLT Order "Spliiting" Help
Author: Jeffrey Lynch
Date: 26 Feb 2005 12:34 AM
I have an inbound document as shown below.

<Orders>
<Order>
<Header OrderNo="123"></Header>
<Line Item="ABC" Date="02-25-2005"></Line>
<Line Item="DEF" Date="02-26-2005"></Line>
<Line Item="YXZ" Date="02-26-2005"></Line>
<Footer NoLines="3"></Footer>
</Order>
</Orders>

I need help creating the map to transform to this if possible:

<Orders>
<Order>
<Header OrderNo="123"></Header>
<Line Item="ABC" Date="02-25-2005"></Line>
<Footer NoLines="1"></Footer>
</Order>
<Order>
<Header OrderNo="123"></Header>
<Line Item="DEF" Date="02-26-2005"></Line>
<Line Item="YXZ" Date="02-26-2005"></Line>
<Footer NoLines="2"></Footer>
</Order>
</Orders>

Basically, I need to split the single <Order></Order> into multiple
<Order></Order> with the same <Header> but with the <Line> items grouped
together by "Date".
Postnext
Ivan PedruzziSubject: XSLT Order
Author: Ivan Pedruzzi
Date: 26 Feb 2005 01:11 AM
Jeffrey,

This is a typical grouping problem, here is one of the possible solutions
Hope this helps
Ivan

<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="item" match="Orders/Order/Line" use="@Date"/>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<Orders>
<xsl:for-each select="Orders/Order/Line">
<xsl:variable name="group" select="key('item', @Date)"/>
<xsl:if test="generate-id($group[1]) = generate-id()">
<Order>
<Header orderNo="{../Header/@OrderNo}"/>
<xsl:for-each select="$group">
<xsl:copy-of select="."/>
</xsl:for-each>
<Footer NoLines="{count($group) }"/>
</Order>
</xsl:if>
</xsl:for-each>
</Orders>
</xsl:template>
</xsl:stylesheet>

Posttop
Jeffrey LynchSubject: XSLT Order
Author: Jeffrey Lynch
Date: 26 Feb 2005 10:50 AM
Thanks so much for the help! Your XSLT does exactly what I'm looking for.
   
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