Re: Followup question: was Re: XSLT to populate a SAML

 Hi,

Arrgh :(!!

I think that my English translation was incorrect :(....

To be more correct, precise, I actually want all the elements that are not
JUST DIRECTLY under/in "adrRecord", but ANYWHERE under/in "adrRecord".

My apologies for that :(!!

I ran through the suggestions, and those only output the single element that
is directly under the "adrRecord", and then I realized that my explanation of
what was needed was imprecise....

The elements that I want to have output are all of these (but as
saml:Attribute under inside an saml:AttributeStatement:

 <adrRecord>
 <PN_ID>1111111</PN_ID>
 <personnel>
 <ADM_ORG_CD>urn:NORM:DEPT</ADM_ORG_CD>
 <DOD_ASSOC_CD>urn:NORM:V01</DOD_ASSOC_CD>
 </personnel>
 <enterpriseUser>
 <entUserRoles>a:b:c</entUserRoles>
 </enterpriseUser>
 </adrRecord>

Sorry about that :(!!!

Jim
     On Thursday, February 16, 2023, 06:21:44 PM EST, Liam R. E. Quin
liam@xxxxxxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

 On Thu, 2023-02-16 at 23:10 +0000, ohaya ohaya@xxxxxxxxx wrote:
> B Hi,
>
> <xsl:template match="*[not(*)] and name(..)='adrRecord'">

You're missing a ]

<xsl:template match="*[not(*)] and (name(..) eq 'adrRecord')]">
is probably what i'd write.

or,
<xsl:template match="adrRecord/*[not(*)]"> ....


liam

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Available for XML/Document/Information Architecture/XSLT/
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