Re: XPath expression to extract the hour offset from

Here is a pure XPath 1.0 solution:

substring(substring-before(concat(substring-before(concat($t, ":"), ":"),
"("), "("), 4)

And this expression:

for $t in ("UTC+5", "UTC+1(+2DT)", "UTC-11", "UTC+4:30",
"UTC+9:30(+10:30DT)")
 return
   substring(substring-before(concat(substring-before(concat($t, ":"),
":"), "("), "("), 4)

evaluates exactly to the wanted result-sequence:

+5
+1
-11
+4
+9

https://github.com/dnovatchev/FXSL-XSLT2/blob/master/ExtractingHours.jpg

Thanks,
Dimitre

On Tue, Dec 13, 2022 at 5:49 AM Roger L Costello costello@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Hi Folks,
>
> I have strings that express time offset from UTC. Here are representative
> examples:
>
> UTC+5
> UTC+1(+2DT)
> UTC-11
> UTC+4:30
> UTC+9:30(+10:30DT)
>
> In areas where daylight savings time is observed, the daylight savings
> time is the part in parentheses.
>
> Some offsets have both an hour and minute. The minute portion is after the
> colon.
>
> I need to extract the hour offset. So for the above examples, I need to
> extract:
>
> +5
> +1
> -11
> +4
> +9
>
> This XPath expression seems to do the job:
>
> let $time := "UTC+9:30(+10:30DT)" return
>     if (contains($time,'(')) then
>         let $part := substring-after(substring-before($time,'('),'UTC')
> return
>             if (contains($part,':')) then
>                 substring-before($part,':')
>             else
>                 $part
>     else
>         let $part := substring-after($time,'UTC') return
>             if (contains($part,':')) then
>                 substring-before($part,':')
>             else
>                 $part
>
> Is there a better (simpler, shorter) XPath expression for doing this?
>
> /Roger