Re: XPath expression to extract the hour offset from

<xsl:stylesheet version="2.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform">

 <xsl:template name="m">
  <xsl:sequence select="
 ('UTC+5','UTC+1(+2DT)','UTC-11','UTC+4:30','UTC+9:30(+10:30DT)')!
 replace(.,'UTC([+-][0-9]+).*','$1')
 "/>
 </xsl:template>
</xsl:stylesheet>


produces

+5 +1 -11 +4 +9

David

On Tue, 13 Dec 2022 at 13:49, Roger L Costello costello@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Hi Folks,
>
> I have strings that express time offset from UTC. Here are representative
> examples:
>
> UTC+5
> UTC+1(+2DT)
> UTC-11
> UTC+4:30
> UTC+9:30(+10:30DT)
>
> In areas where daylight savings time is observed, the daylight savings
> time is the part in parentheses.
>
> Some offsets have both an hour and minute. The minute portion is after the
> colon.
>
> I need to extract the hour offset. So for the above examples, I need to
> extract:
>
> +5
> +1
> -11
> +4
> +9
>
> This XPath expression seems to do the job:
>
> let $time := "UTC+9:30(+10:30DT)" return
>     if (contains($time,'(')) then
>         let $part := substring-after(substring-before($time,'('),'UTC')
> return
>             if (contains($part,':')) then
>                 substring-before($part,':')
>             else
>                 $part
>     else
>         let $part := substring-after($time,'UTC') return
>             if (contains($part,':')) then
>                 substring-before($part,':')
>             else
>                 $part
>
> Is there a better (simpler, shorter) XPath expression for doing this?
>
> /Roger