|
[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
[Recent Entries]
[Reply To This Message]
Re: XSLT program outputs a series of items, how to in
On 25.06.2020 15:25, Roger L Costello costello@xxxxxxxxx wrote:
Hi Martin,
I gave your suggestion a try (although, since I am running a Windows
machine, I used CRLF as the separator):
<xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation,
')')" separator="
"/>
Unfortunately, in the output the items are not separated by newlines. Any
thoughts on why that is?
My suggestion is to replace the whole for-each with the single value-of
I posted.
-----Original Message-----
From: Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, June 25, 2020 9:17 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [EXT] Re: XSLT program outputs a series of items, how to
insertnewlines between each item?
On 25.06.2020 15:11, Roger L Costello costello@xxxxxxxxx wrote:
Hi Folks,
My XSLT program has a loop. Each iteration outputs an item. I want each
item on a new line. The following works. Is there a better way to insert
newlines than by using xsl:text with the end tag on the next line? /Roger
<xsl:output method="text" />
<xsl:template match="/">
<xsl:for-each select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration">
<xsl:value-of select="concat(@value, ' (',
xs:annotation/xs:documentation, ')')/>
<xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
I would use xsl:value-of separator
<xsl:value-of select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration/concat(@value, ' (',
xs:annotation/xs:documentation, ')')" separator=" "/>

|
PURCHASE STYLUS STUDIO ONLINE TODAY!
Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!
Download The World's Best XML IDE!
Accelerate XML development with our award-winning XML IDE - Download a free trial today!
Subscribe in XML format
| RSS 2.0 |
|
| Atom 0.3 |
|
|