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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: XSLT program outputs a series of items, how to in
Hi Martin,
I gave your suggestion a try (although, since I am running a Windows machine,
I used CRLF as the separator):
<xsl:value-of select="concat(@value, ' (', xs:annotation/xs:documentation,
')')" separator="
"/>
Unfortunately, in the output the items are not separated by newlines. Any
thoughts on why that is?
/Roger
-----Original Message-----
From: Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, June 25, 2020 9:17 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [EXT] Re: XSLT program outputs a series of items, how to
insertnewlines between each item?
On 25.06.2020 15:11, Roger L Costello costello@xxxxxxxxx wrote:
> Hi Folks,
>
> My XSLT program has a loop. Each iteration outputs an item. I want each item
on a new line. The following works. Is there a better way to insert newlines
than by using xsl:text with the end tag on the next line? /Roger
>
> <xsl:output method="text" />
>
> <xsl:template match="/">
> <xsl:for-each select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration">
> <xsl:value-of select="concat(@value, ' (',
xs:annotation/xs:documentation, ')')/>
> <xsl:text>
> </xsl:text>
> </xsl:for-each>
> </xsl:template>
I would use xsl:value-of separator
<xsl:value-of select="//xs:simpleType[@name eq
'DatumCode']//xs:enumeration/concat(@value, ' (',
xs:annotation/xs:documentation, ')')" separator=" "/>
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