[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: compare two node sets
Thank you, David, Michael, and Liam for the prompt replies! Michael's
solution seems to be the simplest to implement. I use Saxon 9 HE, so
XPath 2.0 should be okay. And, indeed, quadratic performance should not
be an issue. However, Saxon throws the following error:
XPST0003: Unexpected token "every" at start of expression Is there a typo in the expression? I used the expression as given: <xsl:when test="count(//director) eq count(//author) and every $d in //director satisfies some $a in //author satisfies deep-equal($d/*, $a/*)"> To clarify, the context node is the <film> element. Wolfhart On 19.01.20 17:55, Liam R. E. Quin liam@xxxxxxxxxxxxxxxx wrote: On Sun, 2020-01-19 at 20:37 +0000, Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx wrote:Hello,Why?
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