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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: stop the processing of default attributes?
 I am trying to get my output to replicate the input as best possible. then you want to replace <xsl:element name="{name()}"> <xsl:for-each select="@*"> <xsl:attribute name="{name(.)}"><xsl:value-of select="."/></xsl:attribute> </xsl:for-each> by <xsl:copy> <xsl:copy-of select="@*"/> the namespace differences are that for both xsl:element and xsl:attribute, given an input of x:foo then xsl:copy(-of) will generate a node with the same namespace and local name as the source 9and if possible the same prefix) whereas <xsl:element name="{name()}"> will work like a literal element in the stylesheet: <x:foo> which will generate an element with prefix x and local name foo and whatever namespace URI is bound to x _in the stylesheet_ the namespace of x:foo in the source will not be used. David
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