Re: xslt 1.0 vs xslt 2.0 problem

Hi Mark,

//A[ contains(B/@a, "foo") ]

is going to return just A nodes that have B/@a with "foo" in it... so
it should actually return

<resp>
  <A>
   <B a="foo bar bar"></B>
   <B a="bar bar foo"></B>
   <B a="boo far far"></B>
  </A>
  <A>
   <B a="far boo"></B>
   <B a="foo bar foo"></B>
   <B a="bar foo bar"></B>
  </A>
 </resp>

Because each of the A elements contain a B/@a with "foo" in it.

If you just want
<resp>
  <A>
   <B a="foo bar bar"></B>
   <B a="bar bar foo"></B>
  </A>
  <A>
   <B a="foo bar foo"></B>
   <B a="bar foo bar"></B>
  </A>
 </resp>

Others correctly suggested  //A[B[contains(@a, "foo")]]

But this will still just select the same 2 AA elements with the B
elements unchanged.

I think you want to do something like:

<xsl:for-each select=" //A[B[contains(@a, "foo")]]">
   <A>
      <xsl:apply-templates select="B[contains(@a, "foo")]"/>
  </A>
</xsl:for-each>

This way you are selecting each of the desired A elements... and
filtering out the B elements that do not have the correct @a values.

Darcy
On Wed, Sep 3, 2008 at 1:27 PM, mark bordelon <markcbordelon@xxxxxxxxx> wrote:
> Dear Gents:
>
> I have looked everywhere for the solution to this problem and never seem to get what to the root of the issue. Here is the problem in a nutshell:
>
> I have XML of this structure:
>
> <resp>
>  <A>
>   <B a="foo bar bar"></B>
>   <B a="bar bar foo"></B>
>   <B a="boo far far"></B>
>  </A>
>  <A>
>   <B a="far boo"></B>
>   <B a="foo bar foo"></B>
>   <B a="bar foo bar"></B>
>  </A>
> </resp>
>
> Using XSLT 1.0 (which I must, since I am constrained to use ASP.NET 2.0) I need to query the XML above to find all <A> if any of its children <B> fulfill a certain requirement.
>
> //A[ contains(B/@a, "foo") ]
>
> What I am seeing is that this XSL only checks the FIRST child node's (B) attribute instead of checking all of them. In other words, I only get this:
> <resp>
>  <A>
>  <B a="foo bar bar"></B>
>  </A>
> </resp>
> ...instead of what I need, namely this:
> <resp>
>  <A>
>  <B a="foo bar bar"></B>
>  <B a="bar bar foo"></B>
>  </A>
>  <A>
>  <B a="foo bar foo"></B>
>  <B a="bar foo bar"></B>
>  </A>
> </resp>
>
> An attempt to alleviate this problem by amalgamating all the <B> together using string-join, i.e.
>
> //A[ contains( string-join(B/@a), "foo") ]
>
> error-out because string-join is XSLT 2.0
>
> So...what is the correct way to query through all child nodes using xslt 1.0?
>
> Thanks Guys!
>
> Sincerely,
> Mark Bordelon
> Getty Trust