[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: populating table with sorted elements
I think this requires two passes: first sorting, then grouping. So it should be no problem if you are using XSLT 2.0, or XSLT 1.0 with the node-set() extension. With plain XSLT 1.0 it may be difficult to achieve in a single pass. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Christian Marc Schmidt [mailto:christianmarc@xxxxxxxxx] > Sent: 29 July 2006 15:43 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: populating table with sorted elements > > I am a newcomer to XML/XSLT and am struggling with a bit of > code in which I am attempting to populate a six-column table, > while allowing an xsl:sort. > > Here is a section of my current code: > > <?xml version="1.0" encoding="utf-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > ... > > <table width="970" border="0" cellspacing="0" cellpadding="0"> > <xsl:for-each select="xml/work/*[position() mod 6 = 1]"> > <tr> > <xsl:apply-templates > select=".|following-sibling::*[position() < 6]" /> > </tr> > </xsl:for-each> > </table> > > ... > > The XML structure I've set up looks like this: > > <xml> > <work> > <piece> > </piece> > <piece> > </piece> > ... > </work> > </xml> > > How would I go about adding sort functionality? It seems like > it would be easy enough, yet all of my attempts so far have failed... > > Any suggestions would be much appreciated! > > > Christian
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