[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] populating table with sorted elements
I am a newcomer to XML/XSLT and am struggling with a bit of code in which I am attempting to populate a six-column table, while allowing an xsl:sort. Here is a section of my current code: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> ... <table width="970" border="0" cellspacing="0" cellpadding="0"> <xsl:for-each select="xml/work/*[position() mod 6 = 1]"> <tr> <xsl:apply-templates select=".|following-sibling::*[position() < 6]" /> </tr> </xsl:for-each> </table> ... The XML structure I've set up looks like this: <xml> <work> <piece> </piece> <piece> </piece> ... </work> </xml> How would I go about adding sort functionality? It seems like it would be easy enough, yet all of my attempts so far have failed... Any suggestions would be much appreciated! Christian
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