[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Re: xsl-list Digest 1 Jun 2006 05:10:01 -0000 Issu
David,
Below is the XSLT that I am currently trying to use. The portion above the first comment creates the structure that I want except that it doesn't include the <Root> element that the <Story> element is contained in. Then when I add the instructions below the first comment to try to rename the elements, I lose the structure and tags that I want. My XML file structure is as such: <Root> <Story> <articleTitle>Content</articleTitle> <articleSubTitle>Content</articleSubTitle> <author><authorFname>content</authorFname></author> This is my stylesheet: <xsl:template match="Story"> <xsl:copy> <BB><TG> <xsl:apply-templates select="articleTitle|articleSubTitle"/> </TG></BB> <xsl:apply-templates select="*[not(self::articleTitle or self::articleSubTitle)]"/> </xsl:copy> </xsl:template> <!--Above this line creates the directory structure that I need--> <xsl:template match="Root"> <DG> <xsl:apply-templates select="@*|node()"/> </DG> </xsl:template> <xsl:template match="Story"> <D> <xsl:apply-templates select="@*|node()"/> </D> </xsl:template> <chad/> Chad Chelius AGI Training cchelius@xxxxxxxxxxxxxxx On Jun 1, 2006, at 12:05 PM, David Carlisle wrote: I need all of the other elements to come over as well and I need to rename those elements.yes that's what the <xsl:apply-templates select="*[not(self::title or self::subtitle)]"/> is doing, applying your templates to all the child elements. Sounds like you don't want document to go to document though so change <xsl:copy> to <D>
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