Re: Re: xsl-list Digest 1 Jun 2006 05:10:01 -0000 Issu

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Subject: Re: Re: xsl-list Digest 1 Jun 2006 05:10:01 -0000 Issue 793
From: Chad Chelius <cchelius@xxxxxxxxxxxxxxx>
Date: Thu, 1 Jun 2006 16:39:38 -0400

David, I think this is making more sense now. The first part of the template below, creates the parent elements like we had discussed before, and the tags for the child elements of <Story> in this case don't start to show up until I tell them to like in the second part of the template. One thing that I have run into is the fact that I need to rename the <Story> element after or during processing. How do I accomplish something like that?

<xsl:template match="Story"> <xsl:copy> <BB><TG><TI> <xsl:apply-templates select="articleTitle| articleSubTitle"/> </TI></TG></BB> <xsl:apply-templates select="*[not(self::articleTitle or self::articleSubTitle)]"/> </xsl:copy> </xsl:template>

<-- Second part -->

    <xsl:template match="Root">
        <DG>
            <xsl:apply-templates select="@*|node()"/>
        </DG>
    </xsl:template>

chad

On Jun 1, 2006, at 12:05 PM, David Carlisle wrote:

I need all of the other elements to come over as
well and I need to rename those elements.
yes that's what the
 <xsl:apply-templates select="*[not(self::title or self::subtitle)]"/>
is doing, applying your templates to all the child elements.
Sounds like you don't want document to go to document though so change
 <xsl:copy>  to <D>
and when I said

you just need a standard identity template,
read that as "you just need the templates doing whatever transformation they are doing"

David

Current Thread
Re: xsl-list Digest 1 Jun 2006 05:10:01 -0000 Issue 793 Chad Chelius - 1 Jun 2006 15:51:05 -0000 David Carlisle - 1 Jun 2006 16:11:55 -0000 Chad Chelius - 1 Jun 2006 17:42:10 -0000 David Carlisle - 1 Jun 2006 23:48:11 -0000 Chad Chelius - 1 Jun 2006 21:08:19 -0000 <= Mulberry Technologies List Owner - 1 Jun 2006 21:38:59 -0000

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