Re: Finding the position of an ancestor

<xsl:template match="Step">
   <xsl:apply-templates select="descendant::Chunk[@type='FieldRef']">
        <xsl:with-param name="pos" select="position()"/>
    </xsl:apply-templates>

<xsl:emplate match="Chunk">
   <xsl:param name="pos"/>
   <!-- Field processing goes here -->
</xsl:template>

I was wondering if someone can help me work out a position issue I'm struggling with.

I've got some XML that has is in it :

<FMPReport>
<File>
<ScriptCatalog>
<Script>
<StepList>
<Step>
...
</Step>
<Step>
...
</Step>
<Step>
...
</Step>
<Step id="1" name="Perform Script" enable="True">
<Value>
<DisplayCalculation>
<Chunk type="FieldRef">
<Field id="32867" name="cPref Server Temp Folder" table="gPrefs" />

Then in the xslt I run a for each loop

<xsl:for-each select="/FMPReport/File/ descendant::Chunk[@type='FieldRef']/Field">
<xsl:call-template name="RESULTSET" />
</xsl:for-each>

which works fine, and I can get the data I need. I grab the name from the Step using :

<xsl:value-of select="ancestor::Step[1]/@name" />

But how do I grab the step number? For example I want to know that this is step 4 in this script, by counting how many <Step> elements there are in the current <Script> element. I thought it would just be :

<xsl:value-of select="ancestor::Step[1]/position ()"/>

But that doesn't work, and gives me a parsing error. Am I maybe going about the whole thing wrong?

Thanks,
Nick