[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to avoid a blank line
> Are you generating HTML? Do you mean you have a blank line in the HTML > source, or a blank line on the screen as shown by the browser? It's a switching forth and back between one large file suitable for editing and many small xml files which are meant for a browser. One of those (warning: lines 5 and 6 contain utf-8 chars): <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet href="../view-index.xsl" type="text/xsl"?> <body xmlns="http://www.w3.org/1999/xhtml"> <h3>Dr. Johann Aichholz</h3> b1520, +1580 Wien <br/>b Wien, Anna <br/>Beruf: Mediziner <div class="index"> <a href="../Indices/Index.html">Personen-Index</a> <span>Quellen:</span> <a href="../Regesten/A1581-08-02-00535.xml">1581-08-02</a> </div> </body> > That kind of change has to be done in the template rules for those text > nodes. Need to see more detail if you want more specific advice. True. This is my stylesheet: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xpath-default-namespace="http://www.w3.org/1999/xhtml" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:variable name="LF" select="'
'" /> <xsl:output method="xml"/> <xsl:template match="node() | @*"> <xsl:copy> <xsl:apply-templates select="node() | @*"/> </xsl:copy> </xsl:template> <xsl:template match="body"> <xsl:apply-templates select="node() | @*"/> </xsl:template> <xsl:template match="div[@class='index']"/> <xsl:template match="/"> <xsl:value-of select="$LF"/> <doc> <xsl:for-each select="collection('Tests/Indices?select=*.xml')"> <xsl:value-of select="$LF"/> <reg><xsl:apply-templates select="body"/></reg> </xsl:for-each> <xsl:value-of select="$LF"/> </doc> </xsl:template> </xsl:stylesheet> May I mention an other question (subject: Up-conversion using XSLT 1.0) I've posted several days ago? Regards, Manfred Staudinger
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