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RE: only display if subnodes occur more than once
Subject: RE: only display if subnodes occur more than once
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Tue, 05 Jul 2005 14:47:47 -0400
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Hi,
At 01:01 PM 7/3/2005, it was written:
You could use keys to identify the elements to output. Thus, your input:
<root>
<sub_a>
<elem_1/>
<elem_2/>
<elem_3/>
</sub_a>
<sub_b>
<elem_1/>
<elem_2/>
<elem_2/>
<elem_2/>
<elem_3/>
</sub_b>
<sub_c>
<elem_1/>
<elem_2/>
<elem_3/>
</sub_c>
</root>
Against this transform:
<?xml version="1.0" encoding="iso8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key match="/*/*" name="kElems" use="*"/>
<xsl:template match="root">
<xsl:copy>
<xsl:for-each select="*">
<xsl:if test="count(key('kElems', .)) != count(*)">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Yields:
<?xml version="1.0" encoding="UTF-8"?>
<root>
<sub_b>
<elem_1/>
<elem_2/>
<elem_2/>
<elem_2/>
<elem_3/>
</sub_b>
</root>
You could again use a key to identify and eliminate elements such as
<elem_1>. In fact *I* should do that, to match your required output ...
but I need to use a composite key for that ... and it isn't coming to me
right away. If somebody else has more ready insight, please post.
Could the requirements here be restated please?
If I am not mistaken, the code posted, given this document as input,
effectively copies those children of the document element ('root') that do
not have exactly three children ... because (again, given the input) the
expression count(key('kElems', .)) will always return 3. This is because
the value returned by "." is an empty string "" (notice whitespace is being
stripped), which happens to be the value of all element children ("*") of
all elements matching the key ("/*/*").
I find it hard to believe that's what was wanted. Guessing from the posted
subject line, I think the best approach is rather something like
<xsl:template match="/*/*">
<xsl:if test="*[count(../*[name()=name(current())]) > 1]">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:template>
This says "copy an element child of the document element if it has any
children whose parent has more than one element with the same name as the
child"....
Note: not tested.
Cheers,
Wendell
======================================================================
Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc. http://www.mulberrytech.com
17 West Jefferson Street Direct Phone: 301/315-9635
Suite 207 Phone: 301/315-9631
Rockville, MD 20850 Fax: 301/315-8285
----------------------------------------------------------------------
Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================
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