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Re: only display if subnodes occur more than once

Subject: Re: only display if subnodes occur more than once
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 5 Jul 2005 22:46:03 +0100
xsl for each once
If the input is modified so that sub_b has two groups of repeated
elements then the code I just posted repeats the containing element for
each group.

$ saxon submode.xml  submode.xsl
<?xml version="1.0" encoding="utf-8"?>
<root>
   <sub_b>
      <elem_2/>
      <elem_2/>
      <elem_2/>
   </sub_b>
   <sub_b>
      <elem_3/>
      <elem_3/>
   </sub_b>
</root>

It may be that you'd prefer these to be re-merged:

$ saxon submode.xml  submode.xsl
<?xml version="1.0" encoding="utf-8"?>
<root>
   <sub_b>
      <elem_2/>
      <elem_2/>
      <elem_2/>
      <elem_3/>
      <elem_3/>
   </sub_b>
</root>


in which case the stylesheet is a copule of lines longer:


<xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>

<xsl:output indent="yes"/>

<xsl:key name="x" match="root/*/*"
use="concat(generate-id(..),':',name())"/>
<xsl:template match="root">
<root>
<xsl:for-each select="*">
<xsl:variable name="d"
select="*[generate-id()=generate-id(key('x',concat(generate-id(..),':',name()))[2])]"/>
<xsl:if test="$d">
<xsl:copy>
<xsl:for-each select="$d">
<xsl:copy-of select="key('x',concat(generate-id(..),':',name()))"/>
</xsl:for-each>
</xsl:copy>
</xsl:if>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>



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