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Re: combining the children of similar nodes under one
Subject: Re: combining the children of similar nodes under one node
From: David Montalvo <damontal@xxxxxxxxxxx>
Date: Sun, 7 Mar 2004 12:43:34 -0500
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Thanks Andreas. I'll give it a try. Is that method you suggested known
as the Meunchian method? I remember reading about it somewhere...
dave
Sounds like a grouping-problem...
Try something like:
<xsl:stylesheet ...>
<xsl:key name="prods-by-name" match="product" use="name" />
<xsl:key name="style-type-by-prod" match="style | type"
use="concat(parent::product/name,.)" />
<xsl:variable name="distinct-prods"
select="//product[generate-id(.)=generate-id(
key('prods-by-name',name))]" />
<xsl:template match="root">
<xsl:apply-templates select="$distinct-prods" mode="merge"/>
</xsl:template>
<xsl:template match="product" mode="merge">
<xsl:copy>
<xsl:copy-of select="name" />
<xsl:apply-templates select="key('prods-by-name',name)"
mode="list" />
</xsl:copy>
</xsl:template>
<xsl:template match="product" mode="list">
<xsl:apply-templates select="(style |
type)[generate-id(.)=generate-id(
key('style-type-by-prod',concat(
current()/name,.)))]" />
</xsl:template>
<xsl:template match="style | type">
<xsl:copy-of select="." />
</xsl:template>
</xsl:stylesheet>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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