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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] combining the children of similar nodes under one node
 <inventory> <product> <name>chair</name> <style>rocking</style> </product> <product> <name>chair</name> <type>rocking</type> --> same value as <style> above </product> <product> <name>chair</name> <style>folding</style> <type>lawn</type> </product> </inventory> When I'm in the first node, I grab it, when I'm in the second node, I can check the preceding <style> value and skip it, when I'm in the third node I grab it. That gives me: <product> <name>chair</name> <style>rocking</style> </product> <product> <name>chair</name> <style>folding</style> <type>lawn</type> </product> I figured out that, while in the second of these nodes, I can check if the preceding name is the same and, if so, get the preceding <style> and add it to the second product node, giving me: <product> <name>chair</name> <style>rocking</style> </product> <product> <name>chair</name> <style>rocking</style> <style>folding</style> <type>lawn</type> </product> but I still have 2 products with the name "chair". how can I get the result: <product> <name>chair</name> <style>rocking</style> <style>folding</style> <type>lawn</type> </product> One of the problems is that <style> and <type> are being used interchangeably, but I think I compensated for that. My big problem is getting everything listed under one name with no duplicates. -dave XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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