RE: Re: table sort

I said:
> > <xsl:template match="tbody">
> >   <tbody>
> >    <xsl:apply-templates>
> >     <xsl:sort select="row/entry[1]/para"/>
> >    </xsl:apply-templates>
> >   </tbody>
> > </xsl:template>
> >
> > but it only works with
> >    <xsl:sort/>
> >
> 

Dimitre replied.

> Probably you wanted:
> 
> <xsl:template match="tbody">
>   <tbody>
>    <xsl:apply-templates>
>     <xsl:sort select="entry[1]/para"/>
>    </xsl:apply-templates>
>   </tbody>
> </xsl:template>
> 
> Note that the value of the sort key is calculated relative to 
> the selected
> node. A "row" does not have a "row" child.

The implication of this is that 
when a sort takes place, the context from which the sort takes
place is different from the context of the template (tbody in this case).
at
http://www.w3.org/TR/xslt#sorting

The implication is that the apply-templates (or the sort?)
changes the context to the first child of the context node?
I.e. from tbody to row.

The statement "When a template is instantiated by xsl:apply-templates and
xsl:for-each, the current node list consists of the complete list of nodes
being processed in sorted order."


Is this the statement that changes the context, which makes mine fail 
and Dimitres work?

regards DaveP.



xml input was

  <?xml version="1.0" ?> 
 <table >
 <title>Properties</title> 
 <tgroup cols="3">
 
  <tbody>
   <row>
 <entry>
     <para>A</para> 
    </entry>
    <entry>
     <para>content A</para> 
    </entry>
    <entry /> 
   </row>
   <row>
    <entry>
     <para>X</para> 
    </entry>
    <entry>
     <para>content X</para> 
    </entry>

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