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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: linkdiff template
 On Thu, 13 Jun 2002, Joerg Heinicke wrote:
> Sorry, a litle mistake. It has to be
>
> <xsl:for-each select="document($previous)">
>
> of course.
>
I thought I understood, but I get an "unknown error in XPath" on line 12.
Here is the xsl I'm using: (also tried putting wrapping the key() method
with a boolean() method.
--
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="previous"/>
<xsl:key name="links" match="a" use="@href"/>
<xsl:output method="text"/>
<xsl:template match="a">
<xsl:variable name="href" select="@href"/>
<xsl:for-each select="document($previous)">
<xsl:if test="not(key('links', $href))">
<xsl:value-of select="$href"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
--
Also, it would seem by looking at it, that it would walk through all the
elements of document($previous) for every matching "a" element. Shouldn't
building a key eleminate the need to walk through the tree each time?
Guy
>
> Joerg Heinicke wrote:
> > A key in XSLT is always created for every XML-tree. So you don't need a
> > document() in the key's use-attribute. With your declaration the key of
> > the indexed links is always the value of the first a/@href in $previous.
> >
> > <xsl:key name="links" match="a" use="@href"/>
> >
> > <xsl:param name="previous"/>
> >
> > <xsl:template match="a">
> > <xsl:variable name="href" select="@href"/>
> > <xsl:for-each select="$previous">
> > <xsl:if test="not(key('links', $href))">
> > <xsl:value-of select="$href"/>
> > </xsl:if>
> > </xsl:for-each>
> > </xsl:template>
> >
> > Regards,
> >
> > Joerg
> >
> > Guy McArthur wrote:
> >
> >> Hi, I'm looking to write a template to output the a/@href's from one
> >> (newer) file that are *not* present in another (older) file.
> >>
> >> I.e. given the following two files
> >> -old.xml-
> >> <html>
> >> <a href="http://www.google.com/>Google!</a>
> >> <a href="http://w3.org/">W3C</a>
> >> </html>
> >> -new.xml-
> >> <html>
> >> <a href="http://w3.org/">W3C</a>
> >> <a href="http://guymcarthur.com">My HomePage</a>
> >> <a href="http://xml.apache.org/xalan/">Xalan</a>
> >> </html>
> >> --
> >> The output would be:
> >> http://guymcarthur.com
> >> http://xml.apache.org/xalan/
> >>
> >> Here's my first stab at the stylesheet:
> >> -linkdiff.xsl-
> >> <xsl:stylesheet version="1.0"
> >> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> >>
> >> <xsl:param name="previous"/>
> >>
> >> <xsl:key name="links" match="a" use="document($previous)///a/@href"/>
> >>
> >> <xsl:output method="text"/>
> >>
> >> <xsl:template match="a">
> >> <xsl:if test="not(boolean(key('links', @href)))">
> >> <xsl:value-of select="@href"/>
> >> </xsl:if>
> >> </xsl:template>
> >>
> >> </xsl:stylesheet> --
> >>
> >> However, it is just outputting all the href's (test is always true).
> >> Please enlighten me!
> >>
> >> I'm using 'java org.apache.xalan.xslt.Process -IN new.xml -XSL \
> >> linkdiff.xsl -PARAM previous old.xml'.
> >>
> >> GKM
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
--
--
Guy McArthur * email{guym@xxxxxxxxxxx} http{guymcarthur.com}
LPL Rm. #538 * w{520-621-6373} h{520-326-4555} icq{17470307}
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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