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Re: linkdiff template
Subject: Re: linkdiff template
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Thu, 13 Jun 2002 07:03:15 +0200
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Sorry, a litle mistake. It has to be
<xsl:for-each select="document($previous)">
of course.
Joerg
Joerg Heinicke wrote:
A key in XSLT is always created for every XML-tree. So you don't need a
document() in the key's use-attribute. With your declaration the key of
the indexed links is always the value of the first a/@href in $previous.
<xsl:key name="links" match="a" use="@href"/>
<xsl:param name="previous"/>
<xsl:template match="a">
<xsl:variable name="href" select="@href"/>
<xsl:for-each select="$previous">
<xsl:if test="not(key('links', $href))">
<xsl:value-of select="$href"/>
</xsl:if>
</xsl:for-each>
</xsl:template>
Regards,
Joerg
Guy McArthur wrote:
Hi, I'm looking to write a template to output the a/@href's from one
(newer) file that are *not* present in another (older) file.
I.e. given the following two files
-old.xml-
<html>
<a href="http://www.google.com/>Google!</a>
<a href="http://w3.org/">W3C</a>
</html>
-new.xml-
<html>
<a href="http://w3.org/">W3C</a>
<a href="http://guymcarthur.com">My HomePage</a>
<a href="http://xml.apache.org/xalan/">Xalan</a>
</html>
--
The output would be:
http://guymcarthur.com
http://xml.apache.org/xalan/
Here's my first stab at the stylesheet:
-linkdiff.xsl-
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="previous"/>
<xsl:key name="links" match="a" use="document($previous)///a/@href"/>
<xsl:output method="text"/>
<xsl:template match="a">
<xsl:if test="not(boolean(key('links', @href)))">
<xsl:value-of select="@href"/>
</xsl:if>
</xsl:template>
</xsl:stylesheet> --
However, it is just outputting all the href's (test is always true).
Please enlighten me!
I'm using 'java org.apache.xalan.xslt.Process -IN new.xml -XSL \
linkdiff.xsl -PARAM previous old.xml'.
GKM
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