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Re: XSLT Java Extensions
Subject: Re: XSLT Java Extensions
From: Johannes Döbler <jd@xxxxxxxxxxxxxx>
Date: Tue, 16 Apr 2002 17:51:04 +0200
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Hi Garvin,
Seems I gave an example which does not work. Not being a Xalan extension
expert (for some reasons I prefer to use the infamous XSLT 1.1 xsl:script
instruction) I could not correct it either, but at least I found another
form to declare the extension namespace:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:cal="xalan://java.util.GregorianCalendar">
<xsl:template match="/">
<xsl:variable name="tmp" select="cal:new()"/>
<xsl:value-of select="cal:get($tmp, 1)" />
</xsl:template>
</xsl:stylesheet>
will output 2002 or whatever the current year is.
regards,
Johannes
At 12:40 15.04.2002 -0400, you wrote:
Johannes,
I tried using
<xsl:value-of select="java:java.util.Calendar.get($tmp, 1)">
, but I got the following error on the line where I made the call.
I used the -TS option in Xalan to get results in the console
Line #37, Column #41: value-of, select='' '':
Line #39, Column #76: variable,
select='java:java.util.Calendar.getInstance()':
java.util.GregorianCalendar[time=1018888
758479,areFieldsSet=true,areAllFieldsSet=true,lenient=true,zone=java.util.SimpleTimeZone[id=America/New_York,offset=-180
00000,dstSavings=3600000,useDaylight=true,startYear=0,startMode=3,startMonth=3,startDay=1,startDayOfWeek=1,startTime=720
0000,startTimeMode=0,endMode=2,endMonth=9,endDay=-1,endDayOfWeek=1,endTime=7200000,endTimeMode=0],firstDayOfWeek=1,minim
alDaysInFirstWeek=1,ERA=1,YEAR=2002,MONTH=3,WEEK_OF_YEAR=16,WEEK_OF_MONTH=3,DAY_OF_MONTH=15,DAY_OF_YEAR=105,DAY_OF_WEEK=
2,DAY_OF_WEEK_IN_MONTH=3,AM_PM=1,HOUR=0,HOUR_OF_DAY=12,MINUTE=39,SECOND=18,MILLISECOND=479,ZONE_OFFSET=-18000000,DST_OFF
SET=3600000]
file:///C:/xalan-j_2_0_D07/intact.xsl; Line 40; Column 63
Parser error: TRaX Transform Throwable
XSLT Error (javax.xml.transform.TransformerException): TRaX Transform
Throwable
C:\xalan-j_2_0_D07>
Any ideas?
Garvin
From: Johannes Döbler <jd@xxxxxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: XSLT Java Extensions
Date: Mon, 15 Apr 2002 09:49:40 +0200
<xsl:value-of select="java:java.util.Calendar.get(YEAR)"/>
will invoke the static (non-existent) method "get" in class
java.util.Calendar and pass as parameter the result of evaluating the
child-axis-expression YEAR.
Try instead:
<xsl:value-of select="java:java.util.Calendar.get($tmp, 1)">
This will invoke the non-static method "get" on the Calendar object stored
in variable $tmp and pass number 1 as parameter, which is the value of
constant Calendar.YEAR.
regards,
Johannes
At 19:28 14.04.2002 -0400, you wrote:
Hello ladies/gents, I am trying to use extensions in XSLT to get the
current date/time for textual output, but I don't know how to retrieve
specific data from the object returned.
Below is a sample of the xsl file that makes the extension call:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java">
..
..
<!-- I am making this call inside the template: -->
<xsl:variable name="tmp" select="java:java.util.Calendar.new()"/>
<xsl:value-of select="$tmp" />
..
</xsl:stylesheet>
The problem with this is that, when I instantiate the Calendar object it
returns a GregorianCalendar object with a great deal of information that I
don't want. So when I write it to output, the entire object is returned.
All I need on the text output is YYYYMMDDHHMMSS. These details are stored
in the attributes of the Class.
YEAR MONTH DAY_OF_MONTH HOUR_OF_DAY MINUTE SECOND
I tried using
"<xsl:value-of select="java:java.util.Calendar.get(YEAR)" />" etc., but I
got error messages when the processor tried to process these lines.
Can someone give me some pointers on this?
Thanks
Garvin
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