Re: Need an XPath expression which returns all xs:patt

Is this even possible, theoretically speaking? As soon as you start using
lookaheads, square brackets, and so on, your patterns will likely fail. I
don't think regex can parse regex.

On 4 Apr 2024, 20:15, at 20:15, "David Carlisle d.p.carlisle@xxxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>On Thu, 4 Apr 2024 at 13:29, Roger L Costello costello@xxxxxxxxx <
>xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
>> Hi Folks,
>>
>> I want to find, in an XML Schema, all xs:pattern elements containing
>a
>> regex that permits an unbounded number of characters.
>>
>> Here are examples of xs:pattern elements that I want to find:
>>
>> <xs:pattern value="A*"/>
>> <xs:pattern value="A+"/>
>> <xs:pattern value="A{0,.}"/>
>> <xs:pattern value="A{1,.}"/>
>>
>>
>> How to fix my XPath expression? Is the solution to add a second
>predicate:
>>
>> xs:pattern[
>>         contains(@value, '*') or
>>         contains(@value, '+') or
>>         contains(@value, '{1,}') or
>>         contains(@value, '{0,}')
>>     ][
>>         not(contains(@value, '\*')) and
>>         not(contains(@value, '\+'))
>>     ]
>>
>> Is that correct?
>>
>>
>No.
>
>A  pattern \\*   matches an unbounded list of backslashes  but fails
>your
>test as it contains \*
>A pattern X{5,}  matches an unbounded list  of X of at least 5 but
>doesn't
>match your first predicate.