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Re: Re: efficiently extracting a capture group from a

Subject: Re: Re: efficiently extracting a capture group from analyze-string()
From: "Imsieke, Gerrit, le-tex gerrit.imsieke@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Sat, 4 Jun 2022 17:26:31 -0000
Re:  Re: efficiently extracting a capture group from  a
You can put the matching pattern in a variable in order to avoid redundancy.

The general solution using analyze-string() won't become any easier I'm afraid. You need to declare the fn namespace etc.

On 04.06.2022 19:22, Chris Papademetrious christopher.papademetrious@xxxxxxxxxxxx wrote:
Hi Gerrit, Graydon,

Thanks for having a look!

The tricky part is, I need an empty sequence if the input string does not comply with pattern. replace() returns the original string for a non-match. I could address that with a prefilter:

B replace($file[matches(., '/my-(\w+)\.xml$')], '^.+/my-(\w+)\.xml$', '$1')

but I don't like duplicating patterns because they can accidentally become desynchronized. (If anyone suggests an ENTITY as a solution here, please see me after class.)

Graydon, I need your solution for obtaining the file basename elsewhere in my stylesheet -- thank you!! -- but I run into the prefilter double-pattern issue whether I replace()the full path or just the basename.

And although this example processes a filename, I'd like to find best generalized way to obtain a capture group (or nothing) for any match scenario. In perl, I can assign a variable to the result of a regex match:

B my $file = 'path/my-sometype.xml';

B my ($type) = ($file =~ m{my-(\w+)});

and I was hoping for something similar in XQuery.

Thank you everyone! It's nice to be able to group-think through this.

- Chris

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