Re: Select with multiple conditions?

Michele,

As Eliot notes, the pipe operator in XPath is shorthand for "union", not
"or", although there are places (such as a match pattern) when a union
("give me As and Bs") can look and work like an "or" ("give me things that
are A or B").



So spelled out into long syntax (and keeping only two cases) your first
for-each looks like


<xsl:for-each select="child::*[attribute::level = 'series'] union
child::*[attribute::level = 'subseries']">




borb statements inside the attribute match



<xsl:for-each select="child::*[@level = 'collection' | 'recordgrp' |
'series'  | 'subseries']">

On Wed, Dec 8, 2021 at 9:54 AM Michele R Combs mrrothen@xxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> All three of these constructions appear to be valid (this is xsl 1.0,
> sorry for being antiquated!).  Will there be differences in the output?  If
> not, is one option bbetterb than the others, and if so why?  Ibm
guessing
> that there are no differences in output, and that option 3 is better
> because more concise.  Am I right?
>
>
>
>
>
> borb statements in the select condition:
>
>
>
> <xsl:for-each select="child::*[@level = 'collection']  | child::*[@level =
> 'recordgrp']  | child::*[@level = 'series'] | child::*[@level =
> 'subseries']">
>
>
>
> borb statements inside the node description [ ]
>
>
>
> <xsl:for-each select="child::*[@level = 'collection' | @level =
> 'recordgrp' | @level = 'series' | @level = 'subseries']">
>
>
>
> borb statements inside the attribute match
>
>
>
> <xsl:for-each select="child::*[@level = 'collection' | 'recordgrp' |
> 'series'  | 'subseries']">
>
>
>
>
>
> Michele
>
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>
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>
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>
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