Re: Find/replace algorithm

Hello All,

I have a fairly large XML file similar to this:

<?xml version="1.0" encoding="UTF-8"?>

<products>

<product>ACME Wid Assbly</product>

<product>Ford Eng Rebuild Kit</product>

</products>

I want to do an identity transform except that I want to do some find
and replace on some of the words. For example

Wid = Widget

Assbly = Assembly

Eng = Engine

I am thinking of creating a lookup XML file to drive the find/replace
actions:

<?xml version="1.0" encoding="UTF-8"?>

<lookup>

<entry find="\bWid\b" replace="Widget"/>

<entry find="\bAssbly\b" replace="Assembly"/>

<entry find="\bEng\b" replace="Engine"/>

</lookup>

I am having trouble figuring out a good XSLT 2 or 3 algorithm for
actually doing the replacements. Any suggestions or pointers would be
appreciated. Thank you very much.

Perhaps using fold-left or xsl:iterate for the replace, together with
the ;j or ;n flag to enable support for \b:

  <xsl:param name="lookup">
<lookup>

</lookup>
  </xsl:param>

  <xsl:template match="product/text()">
      <xsl:iterate select="$lookup/lookup/entry">
          <xsl:param name="text" select="."/>
          <xsl:on-completion select="$text"/>
          <xsl:next-iteration>
              <xsl:with-param name="text" select="replace($text, @find,
@replace, ';j')"/>
          </xsl:next-iteration>
      </xsl:iterate>
  </xsl:template>