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Re: Assigning new attribute value

Subject: Re: Assigning new attribute value
From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 20 Dec 2016 20:26:11 -0000
Re:  Assigning new attribute value
On 20.12.2016 21:11, Mark Wilson pubs@xxxxxxxxxxxx wrote:
I am doing an identity transformation that has presented me with a
problem. The element <Location> in the original XML must have one and
only one of seven possible attributes. Whichever attribute is present, I
must keep its name but change its value. I have created a brute-force
template that I assume will work. It ascertains the attribute's name and
assigns it a new value. This is so ugly I am hanging my head in shame.
There must be a more elegant method
Mark

xsl:template match="Location">
     <xsl:param name="placement-index"/>
         <Location>
           <xsl:choose>
               <xsl:when test="@minisheet">
                   <xsl:attribute name="minisheet"
select="$placement-index"/>
               </xsl:when>
               <xsl:when test="@souvenir-sheet">
                   <xsl:attribute name="souvenir-sheet"
select="$placement-index"/>
               </xsl:when>
               <xsl:when test="@gutter">
                   <xsl:attribute name="gutter" select="$placement-index"/>
               </xsl:when>
           </xsl:choose>

<!-- There are more attribute names, but you get the idea -->

         </Location>
  </xsl:template>

So any attribute present gets that new, same value? Then simply do


  <xsl:template match="Location/@*">
    <xsl:param name="placement-index"/>
    <xsl:attribute name="{name()}" select="$placement-index"/>
  </xsl:template>


and have


<xsl:template match="Location">
<xsl:param name="placement-index"/>
<xsl:copy>
<xsl:apply-templates select="@*">
<xsl:with-param name="placement-index" select="$placement-index"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>


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