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Hi Team, I am not able to get required OUTPUT of @sn <link> because of hash (#) problem. Please help in this regard. Input <html> <p>Text. <a href="#bibx" class="bibcit">1</a> xxx <a href="#biby" class="bibcit">2</a></p> <p class="Bib_entry" id='bibx">xxxxxxxxxxxx</p> <p class="Bib_entry" id='biby">xxxxxxxxxxxx</p> </html> output <html> <p>Text. <link rid="bibx" class="bibcit" sn="1">1</link> xxx <link rid="biby" class="bibcit" sn="2">2</a></p> <bib id='bibx" sn="1">xxxxxxxxxxxx</bib> <bib id='biby" sn="2">xxxxxxxxxxxx</bib> </html> Xsl <xsl:key name="ids" match="p[@class = 'Bib_entry'] use="@id"/> <xsl:template match="p[@class='Bib_entry']/@id | @href"> <xsl:for-each select="key('ids', .)"> <xsl:if test="name(.)= 'p'"> <xsl:text/> <xsl:number format="1" count="p[@class = 'Bib_entry']" level="any" from="html"/> </xsl:if> </xsl:for-each> </xsl:template> <xsl:template match="a"> <xsl:variable name="rid" select="substring-after(@href, '#')"/> <xsl:choose> <xsl:when test="@class = 'bibcit'"> <link class="bibcit"> <xsl:attribute name="rid"> <xsl:value-of select="$rid"/> </xsl:attribute> <xsl:attribute name="sn"> <xsl:apply-templates select="@href"/> </xsl:attribute> <xsl:apply-templates/> </link> </xsl:when> </xsl:choose> </xsl:template> <xsl:template match="p[@class='Bib_entry']"> <bib> <xsl:call-template name="id"/> <xsl:attribute name="sn"> <xsl:apply-templates select="@id"/> </xsl:attribute> <xsl:apply-templates/> </bib> </xsl:template> Thanks a lot in advance .JSR
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